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NECO Further Maths OBJ, THEORY/ESSAY Questions and Answer – June/July 2017 Expo Runz

F/Maths Obj:

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11DEAECBECBD

21DDBDEEBEEB

31ACAADEBCED

41ABECBBDEAA

F/Maths Theory solutions

2a)

Log2 (x – 2y) =0——->{1}

Log2 (4y – x) = 1——->{2}

X-2y=2^0——->{1}

-x+4y=2^1——->{2}

X-2y=0

-x+4y=2

2y=2

Y=1

Sub y=1 into eqn{1}

X-2(1)=0

X-2=0

X=2

Therefore X=2 and Y=-1

Further mathematics neco

(1a)

g(x)=y

y=x+6

x=y-6

g^- f(x-6)

=4-5(x-6)/2=4-5x+30/2

=34-5x/2

1b

coodinate=(x1+x2/2 ,y1+y2/2)

7-2/2,7-5/2)

5/2,2/2)

5/2,1)

(2)

(5,2)(-4,k)(2,1)

(y3-y2)/(x3-x2)=(y2-y1)/(x2-x1)

(1-k)/2-(-4)=(k-2)/(-4-5)

(1-k)/(2+4)=(k-2)/-9

(1-k)/6=(k-2)/-9

-9(1-k)=6(k-2)

-9+9k=6k-12

9k-6k=-12+9

3k=-3

k=-1

====================================

(3a)

If f(x+2)=6x^2+5x-8)

To find f(5)

Therefore f(x+2)=f(5)

where x+2=5

x=5-2

x=3

therefore f(5)=6(3)^2+5(3)-8

=6(9)+15-8

=54+7

=61

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